Julien CLEMENT 355dede8e1 fix(typo): add gitignore for public folder and fixed a typo in q-solved

Signed-off-by: Julien CLEMENT <julien.clement@epita.fr>

2022-03-25 22:52:09 +01:00

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Challenge description

quantum reverse | 304 pts 8 solves

I copied the solver of a reversing task from the future. But it doesn't
show the flag forever :thinking:

Given files

circuit.json

TL;DR

The scripts builds a quantum circuit describing an unstructured search algorithm inspired by the grover's algorithm. Its goal is to find among all possible inputs, the one(s) with the highest probability to match a predefined criteria.

It is composed of an oracle and a diffuser. The oracle is a black-box function taking a state vector as input and introducing a phase shift in the target qubit if the input matches the predefined criteria.

The diffuser then performs amplitude amplification using the target qubit's phase kickback when the oracle matches, thus increasing the probability of a matching input vector to be measured.

Basically, the output of the circuit is the input matching the criteria described by the oracle.

All that remains to do for us is to understand what that criteria is.

Reversing the Oracle

We can see that the oracle is built using the circuit.json.

The oracle is composed of 1408 multi-controlled X (MCX) gates, each controlled by 1 or 3 input qubits with with a control state given in the json. Each MCX gate acts on a dedicated ancilla qubit.

After all 1408 MCX, the circuit adds an other MCX on the target qubit with all control states set to 0. The target qubit is therefore introduced a phase shift when all ancillas are in |0>.

So we want all ancillas to be |0> but it is also their original state. We therfore have to influence the control qubits of each MCX so that none actually performs the X gate on any ancilla. This means that among all control qubits of a MCX, at least one must have a state different from its control state, thus deactivating the gate.

If we look closely, we can see that the control state of a control qubit is 1 when the json specifies False, and 0 when True.

Remember, inputs must be different from their control state specified on the gate. Therefore a qubit marked as False, must take value |0> to deactivate the gate. Similarly, a qubit marked True must take value |1>.

So we said earlier that the MCX have either 3 or 1 control bits and that at least 1 of the control qubits must mismatch from their control state.

POC with trivial qubits

Obviously this results in an equation system but let's see what we get with only the obvious qubits: the ones controlling an ancilla by themselves.

Indeed if an ancilla is controlled by a single input qubit then this qubit MUST be different from his control state so the X gate stays disabled. Therefore, any input qubit marked as False and as the only control of a gate MUST be set to |0> to match the oracle. Same is true for qubits marked as True that must be in state |1>.

So let's try to set all obvious qubits:

{{< image src="/q-solved/poc_flag.png" style="border-radius: 8px;" >}}

Well, most of them are 0, except, the first byte: z

Which is a really good sign that we are indead decoding a flag of the form zer0pts{...}

Equation system

For MCX with 3 control bits, we simply need to put them in an equation system, with the trivial qubits.

We will have a total of 1408 equations, 1 for each MCX, each equation basically saying that at least 1 Qubit must be different from its control state, and therefore equal to its assigned boolean in the json.

Once the system is solved, we will know the state of all qubits that match the oracle, which is the one outputed by the quantum circuit. We will then be able to decode it to get the flag.

Solve

I used z3 to build and solve the equation system:

Running the script outputs us the equation system, sat indicating that z3 found a solution to the system and the decoded solution of the system with the flag: zer0pts{FLAG_by_Gr0v3r's_4lg0r1thm}

{{< image src="/q-solved/flag.png" style="border-radius: 8px;" >}}

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